Get ready for Njie <
2) 3
3) an intermediate group High = 163,296, and the lower intermediate group = 35,990
4) 163296 - 35990 = 127 306
5) the extent = 572200-15354 = 556,846
That gross domestic product is distributed in the range of 556,846
What we have created in answer 1, 3, 4 and 5 in the prepared-called measures of dispersion
A
A whole range of data (the largest value - smallest value)
Mediator of the data as a whole
Median upper half of the data (top spring)
Mediator for half the lower data (Near Spring)
Spring term = spring Supreme - Spring Near God is not distracted by
So is 5 standards
×××××××××××××××××××××××××××××××
Aamh idea for a solution: we arrange the data, extract the long, intermediate and then divide the data into two equal parts
Data with high data values with higher extract the highest spring (and median), data values Almnkhvza extract its spring minimum (and median)
Then extract the long spring = spring Supreme - Spring Near
Example 1 <
Verify a claimed disband
Now you will learn the concept of outliers
Extreme values are the values that Ktheira less than the value of the mediator or increase it Ktheiiera
Method identified
Create the lower spring and upper spring and the spring term
Consider the long spring with 1.5 <
1) Near the spring - Q = a <
Example 2 and Aaaaaaaaaaadh and Beyeaaiel
Check with
Arrange, we divide the data into two parts, create spring minimum, Nojaddalrabie the top, we create long-Rubaie, multiply the spring term of 1.5
Resulting pose of the lower spring, We Collect output with spring top, and then judge Are there outliers or not
The solution
Data rank: 557, 494 483 483, 409 454 428, 420 420 385
Spring Top = 483
Near the spring = 420
[] Long-Rubaie [/ b] [/ i] = 483 - 420 = 63
63 × 1.5 = 94.5
Near the spring - 94.5 = 420 - 94.5 = 325.5
Spring top 94.5 = 483 94.5 = 577.5
2) 3
3) an intermediate group High = 163,296, and the lower intermediate group = 35,990
4) 163296 - 35990 = 127 306
5) the extent = 572200-15354 = 556,846
That gross domestic product is distributed in the range of 556,846
What we have created in answer 1, 3, 4 and 5 in the prepared-called measures of dispersion
A
A whole range of data (the largest value - smallest value)
Mediator of the data as a whole
Median upper half of the data (top spring)
Mediator for half the lower data (Near Spring)
Spring term = spring Supreme - Spring Near
So is 5 standards
×××××××××××××××××××××××××××××××
Aamh idea for a solution: we arrange the data, extract the long, intermediate and then divide the data into two equal parts
Data with high data values with higher extract the highest spring (and median), data values Almnkhvza extract its spring minimum (and median)
Then extract the long spring = spring Supreme - Spring Near
Example 1 <
Verify a claimed disband
Now you will learn the concept of outliers
Extreme values are the values that Ktheira less than the value of the mediator or increase it Ktheiiera
Method identified
Create the lower spring and upper spring and the spring term
Consider the long spring with 1.5 <
1) Near the spring - Q = a <
Example 2 and Aaaaaaaaaaadh and Beyeaaiel
Check with
Arrange, we divide the data into two parts, create spring minimum, Nojaddalrabie the top, we create long-Rubaie, multiply the spring term of 1.5
Resulting pose of the lower spring, We Collect output with spring top, and then judge Are there outliers or not
The solution
Data rank: 557, 494 483 483, 409 454 428, 420 420 385
Spring Top = 483
Near the spring = 420
[] Long-Rubaie [/ b] [/ i] = 483 - 420 = 63
63 × 1.5 = 94.5
Near the spring - 94.5 = 420 - 94.5 = 325.5
Spring top 94.5 = 483 94.5 = 577.5
